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9x+20=x^2
We move all terms to the left:
9x+20-(x^2)=0
determiningTheFunctionDomain -x^2+9x+20=0
We add all the numbers together, and all the variables
-1x^2+9x+20=0
a = -1; b = 9; c = +20;
Δ = b2-4ac
Δ = 92-4·(-1)·20
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{161}}{2*-1}=\frac{-9-\sqrt{161}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{161}}{2*-1}=\frac{-9+\sqrt{161}}{-2} $
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